1200k-2k^2=0

Solution for 1200k-2k^2=0 equation:

1200k-2k^2=0

a = -2; b = 1200; c = 0;
Δ = b2-4ac
Δ = 12002-4·(-2)·0
Δ = 1440000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1440000}=1200$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1200)-1200}{2*-2}=\frac{-2400}{-4}
=+600
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1200)+1200}{2*-2}=\frac{0}{-4}
=0
$